Pattern

To print Pattern:
                    *
                *   *
            *   *   *
        *   *   *   *
    *   *   *   *   *


*/


#include <iostream>
using namespace std;

int main(){
     #ifndef ONLINE_JUDGE
        freopen("../asset/input.txt","r",stdin);
        freopen("../asset/output.txt","w",stdout);
    #endif
    // Code here!!
    int n;
    cin>>n;
    
    for(int i=1;i<=n;i++){
        for(int j=0;j<n;j++){
            if(j<n-i)
                cout<<"\t";
            else 
                cout<<"\t*";
        }
        cout<<endl;
    }
    
    return 0;
}

Comments

Must Read:

RDBMS Data Definition Language | Alter-Rename the field

RDBMS Data Definition Language Alter-Rename the field Write a query to change the field name Distributor_name to Distributor_Full_name in Distributor table. Evaluation Result: Result Description Summary of tests +------------------------------+ | 3 tests run / 3 test passed | +------------------------------+

Logic Development | Object Oriented Programming Pre Quiz

Count Encodings

1. You are given a string str of digits. (will never start with a 0) 2. You are required to encode the str as per following rules 1 -> a 2 -> b 3 -> c .. 25 -> y 26 -> z 3. You are required to calculate and print the count of encodings for the string str. For 123 -> there are 3 encodings. abc, aw, lc For 993 -> there is 1 encoding. iic For 013 -> This is an invalid input. A string starting with 0 will not be passed. For 103 -> there is 1 encoding. jc For 303 -> there are 0 encodings. But such a string maybe passed. In this case print 0. Input Format A string str Output Format count of encodings Constraints 0 < str.length <= 10 Sample Input 123 Sample Output 3 Solution: import java.io.*; import java.util.*; public class Main { ...

Count A+b+c+ Subsequences

1. You are given a string str. 2. You are required to calculate and print the count of subsequences of the nature a+b+c+. For abbc -> there are 3 subsequences. abc, abc, abbc For abcabc -> there are 7 subsequences. abc, abc, abbc, aabc, abcc, abc, abc. Input Format A string str Output Format count of subsequences of the nature a+b+c+ Constraints 0 < str.length <= 10 Sample Input abcabc Sample Output 7 Solution: import java.io.*; import java.util.*; public class Main { public static void main(String[] args) throws Exception { Scanner sc = new Scanner(System.in); String str = sc.nextLine(); int counta = 0, countb = 0, countc = 0; for(int i=0;i<str.length();i++){ char ch = str.charAt(i); if(ch == 'a') ++coun...

Basics of Java | Operators | Day 1

Problem: Operators are symbols that perform operations on variables and values. For example, + is an operator used for addition , while * is also an operator used for multiplication . Operators in Java can be classified into 6 types: Arithmetic Operators Assignment Operators Relational Operators Logical Operators Unary Operators Bitwise Operators References: Click Here . We will discuss about arithmetic operators and rest you can study from the references mentioned above. Arithmetic Operators: Arithmetic operators are used to perform arithmetic operations on variables and data. For example, a + b; Here, the + operator is used to add two variables a and b. Similarly, there are various other arithmetic operators in Java. Operator Operation + Addition - Subtraction * Multiplication / Division % Modulo Operation (Remainder after division) Task: You are given two integers as input a and b You need to perform several...

0-1 Pattern

/* @ToDo 0-1 Pattern 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 */ #include <iostream> using namespace std ; int main (){ #ifndef ONLINE_JUDGE freopen ( "../asset/input.txt" , "r" , stdin ); freopen ( "../asset/output.txt" , "w" , stdout ); #endif // Code here!! int n ; cin >> n ; int sign = 1 ; for ( int i = 1 ; i <= n ; i ++){ ...

Reverse a Number

/* @ToDo Reverse a Number 7325 => 5237 12345 => 54321 */ #include <iostream> using namespace std ; int main (){ #ifndef ONLINE_JUDGE freopen ( "../asset/input.txt" , "r" , stdin ); freopen ( "../asset/output.txt" , "w" , stdout ); #endif // Code here!! int n ; cin >> n ; int num = 0 ; while ( n > 0 ){ num = ( num * 10 ) + ( n % 10 ); n /= 10 ; } cout << nu...

RDBMS Data Definition Language | Alter - removing a column in Mobile Specification

RDBMS Data Definition Language Alter - removing a column in Mobile Specification Write a query to remove the column weight from the mobile specification table. Evaluation Result: Result Description Summary of tests +------------------------------+ | 3 tests run / 3 test passed | +------------------------------+

RDBMS Data Definition Language | Alter -Modify the field type

Write a query to change the field type weight varchar(20) in Mobile_specification table to number(10). Result Description Summary of tests +------------------------------+ | 3 tests run / 3 test passed | +------------------------------+

Get's Answer

Search This Blog