Software Engineering Concepts Configuration Management And Version Control Post-Quiz

By Astrio Jather October 30, 2020

Software Engineering Concepts

Configuration Management And Version Control

Post-Quiz

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Accenture PreLearning Software Enginerring

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Count A+b+c+ Subsequences

By Astrio Jather October 14, 2021

1. You are given a string str. 2. You are required to calculate and print the count of subsequences of the nature a+b+c+. For abbc -> there are 3 subsequences. abc, abc, abbc For abcabc -> there are 7 subsequences. abc, abc, abbc, aabc, abcc, abc, abc. Input Format A string str Output Format count of subsequences of the nature a+b+c+ Constraints 0 < str.length <= 10 Sample Input abcabc Sample Output 7 Solution: import java.io.*; import java.util.*; public class Main { public static void main(String[] args) throws Exception { Scanner sc = new Scanner(System.in); String str = sc.nextLine(); int counta = 0, countb = 0, countc = 0; for(int i=0;i<str.length();i++){ char ch = str.charAt(i); if(ch == 'a') ++coun...

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Software Engineering Concepts Basics Of Testing Basics Of Testing | Quiz 2

By Astrio Jather July 22, 2021

Software Engineering Concepts Basics Of Testing Basics Of Testing Quiz 2

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Bubble Sort

By Astrio Jather October 08, 2021

1. You are given an array(arr) of integers. 2. You have to sort the given array in increasing order using bubble sort. Input Format An Integer n arr1 arr2.. n integers Output Format Check the sample ouput and question video. Constraints 1 <= N <= 10000 -10^9 <= arr[i] <= 10^9 Sample Input 5 7 -2 4 1 3 Sample Output Comparing -2 and 7 Swapping -2 and 7 Comparing 4 and 7 Swapping 4 and 7 Comparing 1 and 7 Swapping 1 and 7 Comparing 3 and 7 Swapping 3 and 7 Comparing 4 and -2 Comparing 1 and 4 Swapping 1 and 4 Comparing 3 and 4 Swapping 3 and 4 Comparing 1 and -2 Comparing 3 and 1 Comparing 1 and -2 -2 1 3 4 7 Solution: import java.io.*; import java.util.*; public class Main { public static void bubbleSort(int[] arr) { //write your code here for(int i=0;i<arr.length;i++){ for(int j=1;j<arr.length-i;j++) if(isSmaller(arr,j,j-1)){ ...

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Unbounded Knapsack

By Astrio Jather October 11, 2021

1. You are given a number n, representing the count of items. 2. You are given n numbers, representing the values of n items. 3. You are given n numbers, representing the weights of n items. 3. You are given a number "cap", which is the capacity of a bag you've. 4. You are required to calculate and print the maximum value that can be created in the bag without overflowing it's capacity. Note: Each item can be taken any number of times. You are allowed to put the same item again and again. Input Format A number n v1 v2 .. n number of elements w1 w2 .. n number of elements A number cap Output Format A number representing the maximum value that can be created in the bag without overflowing it's capacity Constraints 1 <= n <= 20 0 <= v1, v2, .. n elements <= 50 0 < w1, w2, .. n elements <= 10 0 < cap <= 10 Sample Input 5 15 14 10 45 30 2 5 1 3 4 7 Sample Output 100 Solution: im...

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Coin Change Permutations

By Astrio Jather October 11, 2021

1. You are given a number n, representing the count of coins. 2. You are given n numbers, representing the denominations of n coins. 3. You are given a number "amt". 4. You are required to calculate and print the number of permutations of the n coins using which the amount "amt" can be paid. Note 1: You have an infinite supply of each coin denomination i.e. same coin denomination can be used for many installments in payment of "amt" Note 2: You are required to find the count of permutations and not combinations i.e. 2 + 2 + 3 = 7 and 2 + 3 + 2 = 7 and 3 + 2 + 2 = 7 are different permutations of same combination. You should treat them as 3 and not 1. Input Format A number n n1 n2 .. n number of elements A number amt Output Format A number representing the cou...

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Butterfly Pattern

By Astrio Jather October 04, 2021

/* @ToDo Butterfly Pattern * * * * * * * * * * * * * * * * * * * * * * *...

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Floyd's Triangle

By Astrio Jather October 04, 2021

/* To Print Floyd's Triangle 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 */ #include <iostream> using namespace std ; int main (){ #ifndef ONLINE_JUDGE freopen ( "../asset/input.txt" , "r" , stdin ); freopen ( "../asset/output.txt" , "w" , stdout ); #endif // Code here!! int n ; cin >> n ; int count = 1 ; for ( int i = 0 ; i < n ; i ++){ for ( int j = 0 ; ...

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Inverted Pattern

By Astrio Jather October 04, 2021

/* @ToDo Inverted Pattern 1 2 3 4 5 1 2 3 4 1 2 3 1 2 1 */ #include <iostream> using namespace std ; int main (){ #ifndef ONLINE_JUDGE freopen ( "../asset/input.txt" , "r" , stdin ); freopen ( "../asset/output.txt" , "w" , stdout ); #endif // Code here!! int n ; cin >> n ; for ( int i = 0 ; i < n ; i ++){ for ( int j = 1 ; j <= n - i ; j ++) ...

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0-1 Pattern

By Astrio Jather October 04, 2021

/* @ToDo 0-1 Pattern 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 */ #include <iostream> using namespace std ; int main (){ #ifndef ONLINE_JUDGE freopen ( "../asset/input.txt" , "r" , stdin ); freopen ( "../asset/output.txt" , "w" , stdout ); #endif // Code here!! int n ; cin >> n ; int sign = 1 ; for ( int i = 1 ; i <= n ; i ++){ ...

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