Software Engineering Concepts Introduction to Agile Technologies Introduction to Agile Technologies

Software Engineering Concepts Introduction to Agile Technologies Introduction to Agile Technologies | Quiz 2

Software Engineering Concepts

Introduction to Agile Technologies

Introduction to Agile Technologies | Quiz 2

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Reverse a Number

/* @ToDo Reverse a Number 7325 => 5237 12345 => 54321 */ #include <iostream> using namespace std ; int main (){ #ifndef ONLINE_JUDGE freopen ( "../asset/input.txt" , "r" , stdin ); freopen ( "../asset/output.txt" , "w" , stdout ); #endif // Code here!! int n ; cin >> n ; int num = 0 ; while ( n > 0 ){ num = ( num * 10 ) + ( n % 10 ); n /= 10 ; } cout << nu...

RDBMS Data Definition Language | Alter -Modify the field type

Write a query to change the field type weight varchar(20) in Mobile_specification table to number(10). Result Description Summary of tests +------------------------------+ | 3 tests run / 3 test passed | +------------------------------+

RDBMS Data Definition Language | Alter-Rename the field

RDBMS Data Definition Language Alter-Rename the field Write a query to change the field name Distributor_name to Distributor_Full_name in Distributor table. Evaluation Result: Result Description Summary of tests +------------------------------+ | 3 tests run / 3 test passed | +------------------------------+

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Count A+b+c+ Subsequences

1. You are given a string str. 2. You are required to calculate and print the count of subsequences of the nature a+b+c+. For abbc -> there are 3 subsequences. abc, abc, abbc For abcabc -> there are 7 subsequences. abc, abc, abbc, aabc, abcc, abc, abc. Input Format A string str Output Format count of subsequences of the nature a+b+c+ Constraints 0 < str.length <= 10 Sample Input abcabc Sample Output 7 Solution: import java.io.*; import java.util.*; public class Main { public static void main(String[] args) throws Exception { Scanner sc = new Scanner(System.in); String str = sc.nextLine(); int counta = 0, countb = 0, countc = 0; for(int i=0;i<str.length();i++){ char ch = str.charAt(i); if(ch == 'a') ++coun...

Mock 3 Slot3 - Handson - 21st July RDBMS (20 Marks) 2.1 Customer details

Write a query to display customer id, customer name, and password of customers whose name starts with 'A'. The password contains the first 3 characters from the name and the first 3 digits from the phone number. Give alias name for password as PASSWORD. Sort the records based on id in descending order. ( Hint: Retrieve data from Customers tables ) Evaluation Result: Result Description Summary of tests:(Note:Your query is evaluated against different datasets. Kindly do not Hardcode) +------------------------------+ | 2 tests run / 2 test passed | +------------------------------+

0-1 Pattern

/* @ToDo 0-1 Pattern 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 */ #include <iostream> using namespace std ; int main (){ #ifndef ONLINE_JUDGE freopen ( "../asset/input.txt" , "r" , stdin ); freopen ( "../asset/output.txt" , "w" , stdout ); #endif // Code here!! int n ; cin >> n ; int sign = 1 ; for ( int i = 1 ; i <= n ; i ++){ ...

Min Cost In Maze Traversal

1. You are given a number n, representing the number of rows. 2. You are given a number m, representing the number of columns. 3. You are given n*m numbers, representing elements of 2d array a, which represents a maze. 4. You are standing in top-left cell and are required to move to bottom-right cell. 5. You are allowed to move 1 cell right (h move) or 1 cell down (v move) in 1 motion. 6. Each cell has a value that will have to be paid to enter that cell (even for the top-left and bottom- right cell). 7. You are required to traverse through the matrix and print the cost of path which is least costly. Input Format A number n A number m e11 e12.. e21 e22.. .. n * m number of elements Output Format The cost of least costly path. Constraints 1 <= n <= 10^2 1 <= m <= 10^2 0 <= e1, e2, .. n * m elements <= 1000 Sample Input 6 6 0 1 4 2 8 2 4 3 6 5 0 4 1 2 4 1 4 6 2 0 7 3 2 2 3 1 5 9 2 4 2 7 0 8 5 1 Sample Output 23 Solution: import java.io.*; import...

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