Skip to main content

RDBMS Data Definition Language | Create Buses table

 efer the below schema and create the buses table.

Column Name

Datatype

Size

Constraint

Constraint name

Bus_no

Number

11

Primary key

PK_BUSES

Bus_name

Varchar2

20


 

Type

Varchar2

20


 

Total_seats

Number

11


 

Avail_seats

Number

11


 


efer the below schema and create the buses table.  Column Name  Datatype  Size  Constraint  Constraint name  Bus_no  Number  11  Primary key  PK_BUSES  Bus_name  Varchar2  20      Type  Varchar2  20      Total_seats  Number  11      Avail_seats  Number  11

 
Result Description  Summary of tests +------------------------------+ | 3 tests run / 3 test passed  | +------------------------------+

 

Result Description

Summary of tests
+------------------------------+
| 3 tests run / 3 test passed  |
+------------------------------+
 


Comments

Must Read:

Zero One Knapsack | Recursion

 1. You are given a number n, representing the count of items. 2. You are given n numbers, representing the values of n items. 3. You are given n numbers, representing the weights of n items. 3. You are given a number "cap", which is the capacity of a bag you've. 4. You are required to calculate and print the maximum value that can be created in the bag without       overflowing it's capacity. Note: Each item can be taken 0 or 1 number of times. You are not allowed to put the same item again and again. Input Format A number n v1 v2 .. n number of elements w1 w2 .. n number of elements A number cap Output Format A number representing the maximum value that can be created in the bag without overflowing it's capacity Constraints 1 <= n <= 20 0 <= v1, v2, .. n elements <= 50 0 < w1, w2, .. n elements <= 10 0 < cap <= 10 Sample Input 5 15 14 10 45 30 2 5 1 3 4 7 Sample Output 75 Solution: import java.io.*; import java.util.*; public class Main...

Count Encodings

 1. You are given a string str of digits. (will never start with a 0) 2. You are required to encode the str as per following rules     1 -> a     2 -> b     3 -> c     ..     25 -> y     26 -> z 3. You are required to calculate and print the count of encodings for the string str.      For 123 -> there are 3 encodings. abc, aw, lc      For 993 -> there is 1 encoding. iic       For 013 -> This is an invalid input. A string starting with 0 will not be passed.      For 103 -> there is 1 encoding. jc      For 303 -> there are 0 encodings. But such a string maybe passed. In this case       print 0. Input Format A string str Output Format count of encodings Constraints 0 < str.length <= 10 Sample Input 123 Sample Output 3 Solution: import java.io.*; import java.util.*; public class Main {   ...

Data Formats ( XML & JSON ) XML AND JSON | Generate XSD for Students

  Generate XSD for Students   Generate XSD for the following XML. XYZ School wants to store the details of students in an xml file. The following scenario helps in designing the XML document. Here StudentList  is the root tag. StudentList contains the entry of each student with rollno, name, age, address and department. <?xml version="1.0" encoding="UTF-8"?> <StudentList  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"  xsi:noNamespaceSchemaLocation="StudentList.xsd">     <Student rollno="2017CSE0055">         <name>             <firstname>Savitha</firstname>         </name>         <age>20</age>         <address>             <doorno>35</doorno>     ...

Climb Stairs With Variable Jumps

 1. You are given a number n, representing the number of stairs in a staircase. 2. You are on the 0th step and are required to climb to the top. 3. You are given n numbers, where ith element's value represents - till how far from the step you       could jump to in a single move.        You can of course jump fewer number of steps in the move. 4. You are required to print the number of different paths via which you can climb to the top. Input Format A number n .. n more elements Output Format A number representing the number of ways to climb the stairs from 0 to top. Constraints 0 <= n <= 20 0 <= n1, n2, .. <= 20 Sample Input 10 3 3 0 2 1 2 4 2 0 0 Sample Output 5 Solution: import java.io.*; import java.util.*; public class Main {     public static void main(String[] args) throws Exception {         // write your code here         Scanner sc = new Scanner(System.in);   ...

Zig Zag Pattern

  /* @ToDo     Zig Zag Pattern         *               *                *       *       *       *        *               *               *        */ #include   <iostream> using   namespace   std ; int   main (){       #ifndef  ONLINE_JUDGE          freopen ( "../asset/input.txt" , "r" , stdin );          freopen (...

Pyramid

/*  To Print  1    2   2    3   3   3    4   4   4   4    5   5   5   5   5    */ #include   <iostream> using   namespace   std ; int   main (){       #ifndef  ONLINE_JUDGE          freopen ( "../asset/input.txt" , "r" , stdin );          freopen ( "../asset/output.txt" , "w" , stdout );     #endif     // Code here!!      int   n ;  cin >> n ;      for ( int   i = 1 ; i <= n ; i ++){          for ( int   j = 1 ; j <=  i ; j ++){     ...

Accenture Mock Quiz | Part 1

Question  1 Incorrect Marked out of 1.00 Remove flag Question text Select the true statement ? Select one: a.  Inheritance forms a is-a part of relationship between classes.   b.  Aggregation is the stronger form of Inheritance. c.  Aggregation forms the is-a type of relationship between classes. d.  Aggregation forms a is-a part of relationship between classes. Composition is the stronger form of Aggregation. Feedback The correct answer is: Aggregation forms a is-a part of relationship between classes. Composition is the stronger form of Aggregation. Question  2 Correct Marked out of 1.00 Flag question Question text What is the diagram that depicts the interaction between objects by arranging the objects in time sequence ? Select one: a.  Use Case Diagram b.  Sequence Diagram   c.  Component Diagram d.  Activity Diagram Feedback The correct answer is: Sequence Diagram Question  3 Incorrect Marked out of 1.00 Flag question...

Algorithm Analysis and Design Concepts Analysis of Algorithms Post-Quiz

 Algorithm Analysis and Design Concepts       Analysis of Algorithms            Post-Quiz  

Software Engineering Concepts Configuration Management And Version Control Post-Quiz

 Software Engineering Concepts       Configuration Management And Version Control            Post-Quiz

Subscribe to Get's Answer by Email