Skip to main content

Java Flow Control And Functions If Else | Day 1

Problem:

In computer programming, we use the if statement to control the flow of the program. For example, if a certain condition is met, then run a specific block of code. Otherwise, run another code.

For example:

 class Main {
  public static void main(String[] args) {

    int number = 0;

    // checks if number is greater than 0
    if (number > 0) {
      System.out.println("The number is positive.");
    }

    // checks if number is less than 0
    else if (number < 0) {
      System.out.println("The number is negative.");
    }

    // if both condition is false
    else {
      System.out.println("The number is 0.");
    }
  }
}


Output

The number is 0.

In the above example, we are checking whether the number is positive, negative, or zero.

Here, we have two condition expressions:

  • number > 0 - checks if the number is greater than 0
  • number < 0 - checks if the number is less than 0

Here, the value of the number is 0. So both the conditions evaluate to false. Hence the statement inside the body of else is executed.

Task:

Given an integer M perform the following conditional actions:

  • If M is multiple of 3 and 5 then print "Good Number" (without quotes).
  • If M is only multiple of 3 and not of 5 then print "Bad Number" (without quotes).
  • If M is only multiple of 5 and not of 3 then print "Poor Number" (without quotes).
  • If M doesn't satisfy any of the above conditions then print "-1" (without quotes).

 

Solution:

import java.lang.*;
import java.util.*;

public class Main {
    public static void main(String[] args) {
        /***Don't change the code here***/
        
        Scanner inp  = new Scanner(System.in);
        int M = inp.nextInt();
        inp.close();
        /*********************************/
        
        /**Write your code here**/
        
        if(M%3==0 && M%5==0){
            System.out.println("Good Number");
        }else if(M%3==0)
            System.out.println("Bad Number");
        else if(M%5==0)
            System.out.println("Poor Number");
        else 
            System.out.println(-1);
    }
}

Comments

Must Read:

Number Pattern

  /* @ToDo     Number Pattern                 1                    1       2                1       2       3            1       2       3       4        1       2       3       4       5            */ #include   <iost...

Software Engineering Concepts Requirement Analysis Post-Quiz

 Software Engineering Concepts       Requirement Analysis            Post-Quiz  Software Engineering Concepts  Requirement Analysis  Post-Quiz Software Engineering Concepts  Requirement Analysis  Test Your Understanding Software Engineering Concepts  Requirement Analysis  Pre-Quiz Software Engineering Concepts  Software Maintenance  Test Your Understanding Software Engineering Concepts  Software Maintenance  Post-Quiz Software Engineering Concepts  Software Maintenance  Pre-Quiz Software Engineering Concepts  Software Engineering Fundamentals  Post-Quiz Software Engineering Concepts  Software Engineering Fundamentals  Pre-Quiz Algorithm Analysis and Design Concepts  Data Structure and Algorithms  Post-Quiz Software Engineering Concepts  Configuration Management And Version Control  Configuration Management And Version Contro...

Software Engineering Concepts Software Maintenance Test Your Understanding

  Software Engineering Concepts       Software Maintenance            Test Your Understanding

Software Engineering Concepts Configuration Management And Version Control Post-Quiz

 Software Engineering Concepts       Configuration Management And Version Control            Post-Quiz

RDBMS Data Definition Language | Create Sales_info table

  Write a query to create Sales_info with constraints mentioned. Refer the below schema  Result Description Summary of tests +------------------------------+ | 3 tests run / 3 test passed | +------------------------------+

Climb Stairs With Variable Jumps

 1. You are given a number n, representing the number of stairs in a staircase. 2. You are on the 0th step and are required to climb to the top. 3. You are given n numbers, where ith element's value represents - till how far from the step you       could jump to in a single move.        You can of course jump fewer number of steps in the move. 4. You are required to print the number of different paths via which you can climb to the top. Input Format A number n .. n more elements Output Format A number representing the number of ways to climb the stairs from 0 to top. Constraints 0 <= n <= 20 0 <= n1, n2, .. <= 20 Sample Input 10 3 3 0 2 1 2 4 2 0 0 Sample Output 5 Solution: import java.io.*; import java.util.*; public class Main {     public static void main(String[] args) throws Exception {         // write your code here         Scanner sc = new Scanner(System.in);   ...

Logic Development | Object Oriented Programming Pre Quiz

 

Unbounded Knapsack

1. You are given a number n, representing the count of items. 2. You are given n numbers, representing the values of n items. 3. You are given n numbers, representing the weights of n items. 3. You are given a number "cap", which is the capacity of a bag you've. 4. You are required to calculate and print the maximum value that can be created in the bag without      overflowing it's capacity. Note: Each item can be taken any number of times. You are allowed to put the same item again                    and again. Input Format A number n v1 v2 .. n number of elements w1 w2 .. n number of elements A number cap Output Format A number representing the maximum value that can be created in the bag without overflowing it's capacity Constraints 1 <= n <= 20 0 <= v1, v2, .. n elements <= 50 0 < w1, w2, .. n elements <= 10 0 < cap <= 10 Sample Input 5 15 14 10 45 30 2 5 1 3 4 7 Sample Output 100 Solution: im...

Count Binary Strings

1. You are given a number n. 2. You are required to print the number of binary strings of length n with no consecutive 0's. Note: In this problem, you are given a number n. All we need to print is the number of binary strings of length n with no consecutive 0's For example: Sample Input: 3 Sample Output: 5 How 5? We have a total of eight binary numbers for length 3, out of which we have 5 numbers in which there are no consecutive zeros. Input Format A number n Output Format A number representing the number of binary strings of length n with no consecutive 0's. Constraints 0 < n <= 45 Sample Input 6 Sample Output 21 Solution: import java.io.*; import java.util.*; public class Main{ public static void main(String[] args) throws Exception {     // write your code here     Scanner sc = new Scanner(System.in);     int n = sc.nextInt();          int dp[][] = new int[n+1][2];     dp[1][0] = 1;     dp[1][1] ...

Subscribe to Get's Answer by Email