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Count Binary Strings

1. You are given a number n.

2. You are required to print the number of binary strings of length n with no consecutive 0's.

Note: In this problem, you are given a number n. All we need to print is the number of binary strings of length n with no consecutive 0's For example: Sample Input: 3 Sample Output: 5 How 5? We have a total of eight binary numbers for length 3, out of which we have 5 numbers in which there are no consecutive zeros.

Input Format
A number n
Output Format
A number representing the number of binary strings of length n with no consecutive 0's.
Constraints
0 < n <= 45
Sample Input
6
Sample Output
21

Solution:

import java.io.*;
import java.util.*;

public class Main{

public static void main(String[] args) throws Exception {
    // write your code here
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    
    int dp[][] = new int[n+1][2];
    dp[1][0] = 1;
    dp[1][1] = 1;
    
    for(int i=2;i<=n;i++){
        dp[i][0] = dp[i-1][1];
        dp[i][1] = dp[i-1][0] + dp[i-1][1];
    }
    
    System.out.println(dp[n][0]+dp[n][1]);
 }

}

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