Skip to main content

Data Formats ( XML & JSON ) XML AND JSON | Generate XSD for Students

 

Generate XSD for Students


 Generate XSD for the following XML.

XYZ School wants to store the details of students in an xml file. The following scenario helps in designing the XML document.

Here StudentList  is the root tag. StudentList contains the entry of each student with rollno, name, age, address and department.

<?xml version="1.0" encoding="UTF-8"?>
<StudentList  xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
xsi:noNamespaceSchemaLocation="StudentList.xsd">
    <Student rollno="2017CSE0055">
        <name>
            <firstname>Savitha</firstname>
        </name>
        <age>20</age>
        <address>
            <doorno>35</doorno>
            <street>NRG Street</street>
            <city>coimbatore</city>
            <pincode>641038</pincode>
        </address>
        <department>CSE</department>
    </Student>

    <Student rollno="2017ECE1050">
        <name>
            <firstname>Vinitha</firstname>
        </name>
        <age>21</age>
        <address>
            <doorno>9</doorno>
            <street>Randy Street</street>
            <city>Chennai</city>
            <pincode>600025</pincode>
        </address>
        <department>ECE</department>
    </Student>

    <Student rollno="2017EEE2044">
        <name>
            <firstname>Steve</firstname>
              <lastname> Johnson </lastname>
        </name>
        <age>19</age>
        <address>
            <doorno>15</doorno>
            <street>CMH Road</street>
            <city>Bangalore</city>
            <pincode>560039</pincode>
        </address>
        <department>EEE</department>
    </Student>
</StudentList>


<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified" 
attributeFormDefault="unqualified">
<xs:element name="StudentList">
<xs:complexType>
<xs:sequence>
<xs:element name="Student" maxOccurs="unbounded" minOccurs="0">
<xs:complexType>
<xs:sequence>
<xs:element name="name">
<xs:complexType>
<xs:all>
<xs:element name="firstname" type="xs:string" minOccurs="0"/>
<xs:element name="lastname" type="xs:string" minOccurs="0"/>
</xs:all>
</xs:complexType>
</xs:element>
<xs:element name="age" type="xs:integer"/>
<xs:element name="address">
<xs:complexType>
<xs:sequence>
<xs:element name="doorno" type="xs:integer"/>
<xs:element name="street" type="xs:string"/>
<xs:element name="city" type="xs:string"/>
<xs:element name="pincode" type="xs:integer"/>
</xs:sequence>
</xs:complexType>
</xs:element>
<xs:element name="department" type="xs:string"/>
</xs:sequence>
<xs:attribute name="rollno" type="xs:string"/>
</xs:complexType>
</xs:element>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:schema>


Evaluation Result:


 

Result Description

Summary of tests
*Note: All the test cases might not have same weightage
+------------------------------+
|  1  test run/ 1  test passed |
+------------------------------+
 

Comments

Must Read:

Pyramid

/*  To Print  1    2   2    3   3   3    4   4   4   4    5   5   5   5   5    */ #include   <iostream> using   namespace   std ; int   main (){       #ifndef  ONLINE_JUDGE          freopen ( "../asset/input.txt" , "r" , stdin );          freopen ( "../asset/output.txt" , "w" , stdout );     #endif     // Code here!!      int   n ;  cin >> n ;      for ( int   i = 1 ; i <= n ; i ++){          for ( int   j = 1 ; j <=  i ; j ++){     ...

Pattern

/* To print:                 *                *   *            *   *   *        *   *   *   *    *   *   *   *   *    */ #include   <iostream> using   namespace   std ; int   main (){       #ifndef  ONLINE_JUDGE          freopen ( "../asset/input.txt" , "r" , stdin );          freopen ( "../asset/output.txt" , "w" , stdout );     #endif     // Code here!!      in...

Coin Change Combination

1. You are given a number n, representing the count of coins. 2. You are given n numbers, representing the denominations of n coins. 3. You are given a number "amt". 4. You are required to calculate and print the number of combinations of the n coins using which the       amount "amt" can be paid. Note 1: You have an infinite supply of each coin denomination i.e. same coin denomination can be                    used for many installments in payment of "amt" Note 2: You are required to find the count of combinations and not permutations i.e.                   2 + 2 + 3 = 7 and 2 + 3 + 2 = 7 and 3 + 2 + 2 = 7 are different permutations of same                    combination. You should treat them as 1 and not 3. Input Format A number n n1 n2 .. n number of elements A number amt Output Format A number representing the count of ...

0-1 Pattern

  /* @ToDo  0-1 Pattern     1     0   1     0   1   0     1   0   1   0     1   0   1   0   1 */ #include   <iostream> using   namespace   std ; int   main (){       #ifndef  ONLINE_JUDGE          freopen ( "../asset/input.txt" , "r" , stdin );          freopen ( "../asset/output.txt" , "w" , stdout );     #endif     // Code here!!      int   n ;  cin >> n ;      int   sign  =  1 ;      for ( int   i = 1 ; i <= n ; i ++){    ...

Pattern

  /* To print Pattern:                     *                 *   *             *   *   *         *   *   *   *     *   *   *   *   * */ #include   <iostream> using   namespace   std ; int   main (){       #ifndef  ONLINE_JUDGE          freopen ( "../asset/input.txt" , "r" , stdin );          freopen ( "../asset/output.txt" , "w" , stdout );     #endif     //...

Goldmine

1. You are given a number n, representing the number of rows. 2. You are given a number m, representing the number of columns. 3. You are given n*m numbers, representing elements of 2d array a, which represents a gold mine. 4. You are standing in front of left wall and are supposed to dig to the right wall. You can start from       any row in the left wall. 5. You are allowed to move 1 cell right-up (d1), 1 cell right (d2) or 1 cell right-down(d3). 6. Each cell has a value that is the amount of gold available in the cell. 7. You are required to identify the maximum amount of gold that can be dug out from the mine. Input Format A number n A number m e11 e12.. e21 e22.. .. n * m number of elements Output Format An integer representing Maximum gold available. Constraints 1 <= n <= 10^2 1 <= m <= 10^2 0 <= e1, e2, .. n * m elements <= 1000 Sample Input 6 6 0 1 4 2 8 2 4 3 6 5 0 4 1 2 4 1 4 6 2 0 7 3 2 2 3 1 5 9 2 4 2 7 0 8 5 1 Sample Output 33 Solution:...

RDBMS Data Definition Language | Alter - Add a column age

  Write a query to add a new column named Age of type number(10) to  Customer_Info table.

RDBMS Data Definition Language | Create Sales_info table

  Write a query to create Sales_info with constraints mentioned. Refer the below schema  Result Description Summary of tests +------------------------------+ | 3 tests run / 3 test passed | +------------------------------+

Zig Zag Pattern

  /* @ToDo     Zig Zag Pattern         *               *                *       *       *       *        *               *               *        */ #include   <iostream> using   namespace   std ; int   main (){       #ifndef  ONLINE_JUDGE          freopen ( "../asset/input.txt" , "r" , stdin );          freopen (...

Subscribe to Get's Answer by Email